f(x)=(x+3)(x^2-4x+20)

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Solution for f(x)=(x+3)(x^2-4x+20) equation: 


Simplifying
f(x) = (x + 3)(x2 + -4x + 20)

Multiply f * x
fx = (x + 3)(x2 + -4x + 20)

Reorder the terms:
fx = (3 + x)(x2 + -4x + 20)

Reorder the terms:
fx = (3 + x)(20 + -4x + x2)

Multiply (3 + x) * (20 + -4x + x2)
fx = (3(20 + -4x + x2) + x(20 + -4x + x2))
fx = ((20 * 3 + -4x * 3 + x2 * 3) + x(20 + -4x + x2))
fx = ((60 + -12x + 3x2) + x(20 + -4x + x2))
fx = (60 + -12x + 3x2 + (20 * x + -4x * x + x2 * x))
fx = (60 + -12x + 3x2 + (20x + -4x2 + x3))

Reorder the terms:
fx = (60 + -12x + 20x + 3x2 + -4x2 + x3)

Combine like terms: -12x + 20x = 8x
fx = (60 + 8x + 3x2 + -4x2 + x3)

Combine like terms: 3x2 + -4x2 = -1x2
fx = (60 + 8x + -1x2 + x3)

Solving
fx = 60 + 8x + -1x2 + x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = 60x-1 + 8 + -1x + x2

Simplifying
f = 60x-1 + 8 + -1x + x2

Reorder the terms:
f = 8 + 60x-1 + -1x + x2

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